This is not an easy question to ask: I am talking about ordering list A by the order of matching values found in list B.
Most results talk about ordering list A by an ordering field in list B.
After some thinking, it became really obvious how to do this.
Simply create an empty list, find the index of an item in list A of list B.
list_a = [100, 1, 10] list_b = [1, 10, 100] sorted_list_b_by_list_a = sorted(list_a, key=lambda x: list_a.index(x))
Yuji Tomita 
I think you make a mistake…
In line 4:
sorted_list_b_by_list_a = sorted(list_b, key=lambda x: list_a.index(x))
^^^^^^
This was EXACTLY what I needed right now, thank you very much! It worked with the correction from the other commenter.
Line 4 there is a mistake, replace list_a.index(x) with list_b.index(x)