A common design pattern: truncate a string to X chars if the string is long, and show a ‘…’ to indicate the string has been truncated.
What’s the shortest way to write this code?
http://stackoverflow.com/questions/2872512/python-truncate-a-long-string
x[:10] + (x[10:] and '...')
Yuji Tomita 
Your second colon is in the wrong place; the code needs to be:
x[:10] + (x[10:] and ‘…’)
x[10:] returns the text from index 10 on if it exists, else an empty string. It is that empty string that determines whether the “and” condition is satisfied.
Indeed good eye!
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